(1/x-1)=(3/x^2-1)

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Solution for (1/x-1)=(3/x^2-1) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-1 = 3/(x^2)-1 // - 3/(x^2)-1

1/x-(3/(x^2))-1+1 = 0

1/x-3*x^-2-1+1 = 0

x^-1-3*x^-2 = 0

t_1 = x^-1

1*t_1^1-3*t_1^2 = 0

t_1-3*t_1^2 = 0

DELTA = 1^2-(-3*0*4)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-1)/(-3*2) or t_1 = (-1^(1/2)-1)/(-3*2)

t_1 = 0 or t_1 = 1/3

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

t_1 = 1/3

x^-1-1/3 = 0

1*x^-1 = 1/3 // : 1

x^-1 = 1/3

-1 < 0

1/(x^1) = 1/3 // * x^1

1 = 1/3*x^1 // : 1/3

3 = x^1

x = 3

x = 3

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